Chemistry Paper 2 Questions and Answers - Eagle II Joint 2021 Mock Exams

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INSTRUCTIONS TO THE CANDIDATES:

  • Answer all the questions.
  • All working must be clearly shown where necessary.
  • Mathematical tables and electronic calculators can be used.
  1. Use the table below to answer the questions that follow. (The letters do not represent the actual symbols of the elements).
      Element  Atomic Number   Melting point ° 
      A
      B
      C
      D
      E
        11
        13
        14
        17
        19
        97.8
         660
        1410
         − 101
          63.7
    1. Write the electronic arrangement for the ions formed by element B and D. [2mks]
    2. Select an element which is:
      1. A non-conductor of electricity [1mk]
      2. The most reactive non-metal [1mk]
    3. To which period of the periodic table does element E belong? [1mk]
    4. Element E losses its outermost electron more readily than A. Explain. [1mk]
    5. Use dots (.) and crosses (x) to represent the valence electrons and show the bonding in the compound formed between element C and D. [1mk]
    6. Explain why the melting point of element B is higher than that of element A [1mk]
    7. Write an equation for the reaction that takes place between element A and water. [1mk]
  2.  
    1. The set-up below was used to collect gas F, produced by the reaction between water and calcium metal.
      1. Name gas F [1mk]
      2. At the end of the experiment the solution in the beaker was found to be a weak base. Explain why the solution is a weak base. [1mk]
      3. Give one laboratory use of the solution formed in the beaker. [1mk]
    2. The scheme below shows some reaction starting with calcium oxide. Study it and answer the questions that follow.
                Chem EJM PP2Q2b
      1. Name the reagent used in step 2 and 4 [1mk]
      2. Write an equation for the reaction in step 3 [1mk]
      3. Describe how a solid sample of anhydrous calcium sulphate is obtained in step 5 [3mks]
  3. The figure below is a flow chart showing the process that occurs in the manufacture of nitric (V) acid.
              Chem EJM PP2Q3
    1. Name substance P, Q, R and S.  (4 mks)
    2. To obtain substance R, ammonia is heated at 9000C in the presence of air and a catalyst.
      The product is then cooled in the heat exchanger and mixed with more air.
      1. Name the catalyst for the reaction (1mk)
      2. Write the equation for the reaction described (1mk)
    3. When ammonia is reacted with nitric (V) acid, it produces a nitrogenous fertilizer.
      1. Calculate the percentage of nitrogen in the fertilizer obtained. (N=14,H=1,O=16) (2mks)
      2. State one problem associated with the use of nitrogenous fertilizers. (1mk)
  4. The diagram in Figure below was used to prepare hydrogen chloride gas which was then passed over heated iron powder.
            Chem EJM PP2Q4
    1. Give a pair of reagents that will produce hydrogen chloride gas in flask A. (2mks)
    2. Name the substance in flask B. (1mk)
    3. State the observation made in the combustion tube after the reaction is complete. (1mk)
    4. Write an equation for the reaction in the combustion tube. (1mk)
    5. Describe a chemical test for hydrogen chloride gas. (1mk)
    6. Identify the gas that burns at the jet and explain why the gas is burned.  (1mk)
    7. Give reasons why excess hydrogen chloride gas is dissolved using the funnel arrangement. (1mk)
  5.  
    1. Define the following:
      1. Empirical formula. (1mk)
      2. Molecular formula. (1mk)
    2. A major textile dye manufacturer developed a new yellow dye. The dye has a percent composition of 75.95% Carbon, 17.72% Nitrogen, and 6.33% Hydrogen by mass. Determine;
      1. The empirical formula of the dye. (C=12, H=1, N=14) (3mks)
      2. The molecular formula of the dye, if it has a molar mass of about 237 g/mol. (C=12, H=1, N=14) (2mks)
  6.  
    1.  
      1. Define the term fuel [1mk]
      2. Determine the heating value of ethanol  [2mks]
        (C = 12, H = 1, O = 16) 
        (ΔHc(C2H5OH) = -1368KJ/mol)
    2. The diagram below represents a set-up that was used to determine the enthalpy of combustion of ethanol.
      Geo EJM PP1Q6bThe following results were obtained:
      Volume of water = 500cm3
      Initial temperature of water = 25oC
      Final temperature of water = 38oC
      Mass of ethanol + lamp before heating = 120.5g
      Mass of ethanol + lamp after heating = 119.5g
      1. Calculate the heat evolved
        (Specific heat capacity = 4.2jg-k-, density of water = 1g/cm3) [2mks]
      2. Determine the molar heat of combustion of ethanol (C = 12, H = 1, O = 16) [3mks]
      3. Write the thermochemical equation for the reaction. [1mk]
      4. The theoretical value for the molar enthalpy of combustion of ethanol is -1368kJ/mol
        Why is the value calculated from the experimental results different from this? [1mk]
      5. Define the term molar heat of combustion [1mk]
  7.  
    1.  
      1. Give the systematic name of the following compound.  [1mk]
        CH3CH2COOCH
      2. Draw the structure of 2-methyl but -1, 3-diene [1mk]
    2. The scheme below shows the reactions of organic compounds, study it and answer the questions that follow.
            Chem EJM PP2Q7b
      1. Name the process in step 1 [1mk]
      2. State the condition for the process in step 2 [1mk]
      3. Write the equation for the process in step 4 [1mk]
      4. Name the process taking place in step 3 [1mk]
      5. Name the organic compound A the product of step (IV) [1mk]
      6. Given that the relative formula mass of the product of step (VI) is 56000. Determine the value of n. (C=12, H=1) [2mks]
    3. The flow chart below is a summary of the process involved during preparation of a detergent.
             Chem EJM PP2Q7c
      1. Name the reagent in process 1 [1mk]
      2. Draw the structure of P; Give its name [2mks]
      3. State one advantage of detergent P  Chem EJM PP2Q7cii over COO-Na[1mk]
  8.  
    1. Define the term solubility [1mk]
    2. Experiments were done to determine the solubility of two salts X and Y in water at different temperatures. The following results were obtained:
        Temperature (°C)    Solubility in g/100g of water 
                                  X         Y

           0
          10
          20
          30
          40
          50
          60
          70
          80

            14.0
            17.5
            21.0
            25.0
            28.5
            33.0
            40.0
            47.0
            55.0

            25.0
            27.0
            30.0
            32.5
            35.0
             37.5
             40.0
              42.5
              45.0

      1. On the same axis plot the solubility corves for salts X and Y [5mks]
      2. Determine the solubility of salt Y at 45oC [1mk]
      3. At what temperature is the solubilities of the two salts equal [1mk]
      4. 80g of a saturated solution of salt X was cooled from 75°C to 15°C, determine the mass of salt X that crystallized out [3mks]
      5. A mixture containing 20g of X and 40g of Y in 100g of water at 80°C was cooled to 30°C. Identify the salt that crystallized out. Calculate the mass of the salt that crystallized. [3mks]

MARKING SCHEME

  1.  
    1. B – 2.8 √               
      D – 2.8.8√  (2mks)
    2.  
      1. D √    (1mk)                 
      2. D√ (1mk)
    3. Period 4√ (1mk)
    4. E – has a bigger/greater/larger atomic radius√ hence loses its outermost electrons easily. √ (1mk)
    5.  
      Chem EJM PP2Ans1e√(1mk)
    6. B has more delocalized electrons√1/2 than A hence has stronger metallic bond. √1/2 (1mk)
      OR B has smaller atomic radius√1/2 hence stronger metallic bond√1/2
    7.  2A(s)   +   H2O(l)   arrow      2AOH(aq)  +  H2(g)  (1mk) √
      (Accept if actual symbols used, award 0 if not balanced, penalize half mark for wrong state symbol)
  2.  
    1.  
      1. Hydrogen gas (1mk) (strictly the name)
      2. Ca (OH)  slightly soluble in water, √  only few OH- are produced√½ in  solution.     (1mk)
      3. It is used for testing presence of CO2. √          (1mk)
        Prepare ammonia √ (any one)
    2.  
      1.  
        • Step 2  - carbon (IV) oxide√½ (½mk)
        • Step 4 – Dilute HCL√1/2  (½ mk)
      2. Ca (HCO3)2(aq) arrow    CaCO3(s)     +   CO2(g)   +   H2O(l)     (1mk)
      3.  
        • Add an aqueous solution of sulphuric (VI) acid/Na2SO4/K2SO4    (1mk)
        • Filter to obtain CaSO √   
        • Wash with distilled water√ and dry between filter papers√   
  3.  
    1.  
      • P Hydrogen/nitrogen    1mk
      • Q Nitrogen /hydrogen  1mk
      • R Nitrogen (IV) oxide    1mk
      • S Water      1mk
    2.  
      1. Platinum – rhodium    1mk
      2. 4NH3(g)  +  5O2(g) arrow   4NO(g)  +  6H2O(g)  √   
        2NO(g)   +  O2(g)    arrow    2NO2(g)      √
    3.  
      1. NH4NO3√½ (REM = 80)  √½
        28/80  x 100 √½ = 35% √½
      2.  
        • Lowers soil Ph
        • Increase soil acidity
        • Causes euthrophication
        • Pollution of water
          (any one)
  4.  
    1.  
      • solid sodium chloride/rock salt
      • Concentrated Sulphur (VI) acid
    2. Concentrated Sulphur (VI) acid(penalize formula)
    3. Grey iron powder turns to green iron (II) chloride (acc. Green solid formed)
    4. HCl(g)  +  Fe(s)  arrow      FeCl2(s)    +  H2(g)  1mk
    5. When in contact with ammonia gas, dense white fumes of ammonium chloride are formed  (1mk)
    6. hydrogen gas √½
      • Mixture of hydrogen and air burns explosively√½
    7. to prevent sucking back in increasing surface area for dissolution
  5.  
    1.  
      1. formula showing the simplest whole ratio in which atoms combine to form compound
      2. Formula showing the actual number of each kind of atoms present in molecule of the compound
    2.  
      1.   
        Chem EJM PP2Ans5i
      2. n(79)=237√½
        237 = 3 √½
         79
        C15H15√1
  6.  
    1.  
      1. A substance that burns in air to produce useful energy      (1mk)
      2. CH3CH2OH
        RFM  = 46√½
        = 1368  (√½)      =29.74 kJ/g     (√1mk)
              46
    2.  
      1. ΔH = MCDJ
              = 500 x 4.2 x 13 (1mk)
               = 27,3005
               = 27.3Kj  1mk
        (penalize half mark for wrong units)
      2. Mass of ethanol
        120.5-119.5=1g (√ 1mk)
        1g – 27.3kJ
        46g – 46 x 27.3   (  √ 1mk)
                       1
        = 1255 .8Jk
        = -1255.8kJ/mol   (1mk)(penalize half mark for missing –ve sign Penalize fully for wrong units)
      3. CH3CH2OH(g) +  3O2(g)  arrow  2CO2g  +  3H2OΔH = -1255.8 kJj/mol   (√ 1mk)
      4. heat loss to the surrounding (1mk)
        • Error in measurements of volume and temperature (experiment errors)
      5. Heat change that occur when one mole of a substance burns completely in oxygen. (√ 1mk)
  7.  
    1.  
      1. Methylpropanoate  (√ 1mk)
      2.   
        Chem EJM PP2Ans7i
    2.  
      1. Photosynthesis (√ 1mk)
      2. yeast (√ 1mk)
      3. 2CH3CH2OH  + 2Na arrow  2CH3CH2ONa  +  H2  (√ 1mk)
      4. Oxidation  (√ 1mk)
      5. sodium ethoxide  (√ 1mk)
      6. ?  - (C2H4)  = 56000
        28n = 56000√
        ?n   = 2000√ (2mks)
    3.  
      1. concentrated sulphuric acid  (√ 1mk)
      2.  
        Chem EJM PP2Ans7ci (√ 1mk)
        • Sodium alkylbenzene sulphanoate (√ 1mk)
      3. Does not form scum with hard water (√ 1mk)
  8.  
    1. The maximum mass of a solute that can dissolve in 100g of solvent (water) at a particular temperature to form saturated solution.  (√ 1mk)
    2.  
      1. 36.5g/100g of water   ± 1 (1mk)(Read from correct curve)
      2. 60°C      ± 1  (1mk)
      3.  51.5   x 80   –    28.5  x 80  =  9.452g  (√ 1mk)
        151.5 (√1mk)    128.5 (√ 1mk)
      4. Solubility of g/100g of water at
         Salt        30°C       80°C
          X         25        55    
          Y         32.5         45
        Crystal of y (√ 1mk)
        40 − 32.5 = 7.5g (√ 1mk) 
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