Questions
 A sample of unknown compound gas X is shown by analysis to contain Sulphur and Oxygen. The gas requires 28.3 seconds to diffuse through a small aperture into a vacuum. An identical number of oxygen molecules pass through the same aperture in 20 seconds. Determine the molecular mass of gas X (O= 16, S= 32)

 State Graham’s Law of diffusion
 Gas V takes 10 seconds to diffuse through a distance of one fifth of a meter. Another gas W takes the same time to diffuse through a distance of 10 cm. if the relative molecular mass of gas V is 16.0; calculate the molecular mass of W

 State Charles’ Law
 The volume of a sample of nitrogen gas at a temperature of 291K and 1.0 x 10^{5} Pascals was 3.5 x 10^{2} m^{3}. Calculate the temperature at which the volume of the gas would be 2.8 x 10^{2} m^{3} at 1.0 x 10^{5 }pascals.
 60 cm^{3} of oxygen gas diffused through a porous partition in 50 seconds. How long would it take 60 cm^{3} of sulphur (IV) oxide gas to diffuse through the same partition under the sane conditions? (S = 32.0, O = 16.0)

 State Graham’s law of diffusion
 30cm^{3} of hydrogen chloride gas diffuses through a porous pot in 20 seconds. How long would it take 42cm^{3} of sulphur(IV) oxide gas to diffuse through the same pot under the same conditions (H =1 Cl = 35.5 S = 32 O =16)

 State Boyles law
 Sketch a graph that represents Charles’ law
 A gas occupied a volume of 250 cm^{3} at 23^{º} C and 1 atmosphere. Determine its volume at 127^{º} C when pressure is kept constant.
 A factory produces Calcium Oxide from Calcium Carbonate as shown in the equation below:
heat
CaCO_{3 (s)} → CaO _{(s)} + CO_{2 (g)}What volume of Carbon (IV) Oxide would be produced from 1000kg of Calcium Carbonate at s.t.p (Ca = 40, C = 12, O = 16, Molar gas volume at s.t.p = 22.4dm^{3})  A fixed mass of gas occupies 200 cm^{3} at a temperature of 23oC and pressure of 740mmHg. Calculate the volume of the gas at 25oC and 780mmHg pressure
 Gas K diffuses through a porous material at a rate of 12cm^{3} s^{1} where as S diffuses through the same material at a rate of 7.5cm^{3}s^{1}. Given that the molar mass of K is 16, calculate the molar mass of S
 State Gay Lussac’s law

 What is the relationship between the rate of diffusion of a gas and its molecular mass?
 A sample of Carbon (IV) Oxide takes 200 seconds to diffuse across a porous plug.
How long will it take the same amount of Carbon (II) Oxide to diffuse through the same plug?(C=12, O=16)
 Below are structures of particles. Use it to answer questions that follow. In each case only electrons in the outermost energy level are shown
key
P = Proton
N = Neutron
X = Electron Identify the particle which is an anion
 Choose a pair of isotopes. Give a reason
 The figure below shows two gases P and Q diffusing from two opposite ends 18 seconds after the experiment
 Which of the gases has a lighter density?
 Given that the molecular mass of gas Q is 17, calculate the molecular mass of P
 Identify the particles that facilitate the electric conductivity of the following substances
 Sodium metal
 Sodium Chloride solution
 Molten Lead Bromide
 Gas B takes 110 seconds to diffuse through a porous pot, how long will it take for the same amount of ammonia to diffuse under the same conditions of temperature and pressure? (RMM of B = 34 RMM of ammonia = 17)
 A gas occupies 5dm^{3} at a temperature of 27^{o}C and 1 atmosphere pressure. Calculate the volume occupied by the gas at a pressure of 2 atmospheres and a temperature of 127^{o}C
 A fixed mass of gas occupies 200 cm^{3} at a temperature of 23^{0}c and a pressure of 740 mm Hg. Calculate the volume of the gas at 25^{0}c and 790 mm Hg pressure.

 State the Graham’s law
 100cm^{3} of Carbon (IV) oxide gas diffused through a porous partition in 30seconds. How long would it take 150cm3 of Nitrogen (IV) oxide to diffuse through the same partition under the same conditions? (C = 12.0, N = 14.0, O = 16.0)
Answers


 The rate of diffusion of a gas is inversely proportional to the square root of its density under the same conditions of temperature and pressure

 The rate of diffusion of a gas is inversely proportional to the square root of its density under the same conditions of temperature and pressure

 The volume of a fixed mass of a gas is directly proportional to its absolute temperature at constant Pressure



 The rate of diffusion of a fixed mass of a gas is inversely proportional to the square root of it density at constant temperature and pressure

 The rate of diffusion of a fixed mass of a gas is inversely proportional to the square root of it density at constant temperature and pressure

 Boyles’ law For a fixed mass of a gas, volume is inversely promotional to pressure at constant temperature




 When gases combine they do so in volume which bear a simple ratio to one another and to the product if gaseous under standard temperature and pressure

 Rate of diffusion is whereby proportional to molecular mass of a gas. √1


 Y √1
 Z and W √1 have same atomic number but different mass number. √1

 Gas P


 Delocalized electrons
 Mobile ions
 Mobile ions




 601 √1


 Grahams law states
Under the same conditions of pressure and temperature, the rate of diffusion of a gas is inversely proportional to the square root of its density 
 Grahams law states
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