-
- (11.4 ± 0.2 )cm2
- NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
- mole NaOH = 40g
=0.5g
1 x 0.5/40 = 0.125 moles
= 0.125 moles
0.125 moles NaOH = 250 cm3
?= 100 cm3 - 0.05 × 25/100 = 1.25 × 10-3 Moles
?= 25 cm3 - mole ratio of NaOH:Hcl
1 mole : 1 mole
1.25 × 10-3 :?
1 × 1.25/1 × 10-3 = 1.25 x 10-3 moles
1.25x 10-3 moles = 11.4 cm3
?= 250 cm3
1.25 × 10-3 × 250/11.4= 0.0274 moles - 0.02741 moles= 10cm3
? = 1000cm3
0.02741 × 1000/10 = 2.7412 moles
-
Volume of Solution A (cm3) Volume of distilled water (cm3) Concentration of Solution A (moles/dm3) Time (s) I/t (S-1) I 12 0 2.7412 M 17.75 0.05634 II 10 2 2.2843 M 25.18 0.03970 III 8 4 1.8275 M 36.90 0.02710 IV 6 6 1.3706 M 70.94 0.01410 V 4 8 0.9137 M 178.34 0.005607 -
- 2.7412 moles= 1000cm3
? = 10 cm3
2.7412 x 10/1000 = 0.027412 moles
0.027412 moles = 12 cm3
?= 1000 cm3
0.027412 x 1000/12 = 2.2843 moles
2.712 moles = 1000cm3
? = 5 cm3 - 2.7412 x 5/1000 = 0.02193 moles 10QC,
0.02193 moles= 12cm3
? = 1000cm3
0.02193 × 1000/12 = 1.8275 M
2.7412 moles = 1000 cm3
? = 6cm3
2.7412/1000 × 6 = 0.01645
0.01645 = 12 cm3
? = 1000cm3
0.01645/12 × 1000 = 1.3706 - 2.741 moles= 1000cm3
? = 4 cm3 - 2.7412 = 1000cm3
? = 4
2.7412/100 × 4 = 0.01096 moles
0.01096 moles = 12 cm3
? = 1000cm3
0.01096 × 1000/12 = 0.9137 m
- 2.7412 moles= 1000cm3
- 1/t = 2.0 × 10-3 sec
t = 1/2.0 × 10-3
t = 50 sec
Rate of reaction increase with increase in concentration of the ac
-
Join our whatsapp group for latest updates
Tap Here to Download for 50/-
Get on WhatsApp for 50/-
Download CHEMISTRY PAPER 3 Marking Scheme - 2019 KCSE Prediction Answers Set 1.
Tap Here to Download for 50/-
Get on WhatsApp for 50/-
Why download?
- ✔ To read offline at any time.
- ✔ To Print at your convenience
- ✔ Share Easily with Friends / Students
