BIOLOGY PAPER 3 Marking Scheme - 2019 KCSE Prediction Answers Set 1

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  1.  
    1.  

      FOOD COMPOUND

      PROCEDURE

      OBSERVATION

      CONCLUSION

      Starch

      To 2cm3 of solution L add drops of iodine 1mk

      Colour turns brown /yellow ½ mk

      Starch absent ½ mk

      Reducing sugar

      To 2cm3 of solution L ,add benedicts solution and boil 1 mark

      Colour changes from blue to green to yellow/orange ½ mk

      Reducing sugars present ½ mk

      proteins

      To 2cm3 of solution L add 3 drops of NaOH followed by drops of CuSO4 and shake 1mk

      solution remains blue ½ mk

      Protein absent ½ mk

      Ascorbic acid

      (vitamin c)

      To 2cm3 of solution DCPIP add solution L dropwise shaking till in excess 1mk

      DCPIP decolourised ½ mk

      Vitamin C /Ascorbic acid present ½ mk

    2.  
      1. solution in the visking tubing increases in volume
      2. Water moves by osmosis; in the visking tubing due to the high osmotic pressure of the solution in the visking tubing
    3. Cell membrane/plasma membrane/plasmalema
  1.  
    1.  
      1. A – Endosperm
        B – Radicle
        C – Plumule
        D – Plumule sheath/coleoptile
      2. A – stores food for the embryo;
        D – protects the delicate plumule from mechanical damage;
    2.  
      1. hypogeal;
      2. Kingdom – Plantae; Rej plant
        Division – spermatophyte
        Class –Monocotyledonae; rej monocot/monocotyledon
      3.  
        • Fibrousroots
        • Parallel venation;
        • Floral parts occur in three /multiples of three;
        • Sheath like petiole; Mark first three
    3. Has two scars;



  1.  
    1.  

      Specimen

      steps

      identity

      A

      1b,3a;

      Arachnida

      B

      1a,2a,4a;

      Pisces

      C

      1b,2b,5b,6b;

      Chilopoda

      D

      1a,2a,4b,7b,8a

      Reptilia

      E

      1a,2a,4b,7a;

      Aves

      F

      1b,3b,5a;

      Insecta

    2. Magnification =  Diagram lengthActual length = 50mm/100mm;
      = ×½  or ×0.5;
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