INSTRUCTIONS TO STUDENTS
- All answers and workings must be written on the question paper in the spaces provided below each question
- Show all step in your calculation , giving your answers at each stage in the spaces provided below each question
- Marks may be given for correct working even if the answer is wrong
- Electronic calculators and mathematical tables may be used except where stated otherwise
- Take π =22/7
Questions
SECTION 1(50MKS)
- Evaluate without using a calculator. (3mks)
4 of 20+10÷-5×6
6×9-4÷2+12 - 0.24+-0.3×-0.81 (3mks)
0.08÷0.4 -
- Find the H.C.F of 36 and 54 (1mk)
- If three numbers 36,54 and another number have a G.C.D of 6 and L.C.M of 216, find the other number (2mks)
-
- Simplify the expression (3mks)
3x+4 + x+1 - 2x+8
4 2 3 - Solve for x in the equation below.
2(x+4) =14 (2mks)
- Simplify the expression (3mks)
- Use a number line to work out the following:
- 3+-4 (1mk)
- 5 - - 2 (1mk)
- The length of an arc of a circle is 88cm. Find the radius of the circle if the arc subtends an angle 144° at the centre (Take =22/7) (3mks)
- Four men can build a stone wall 32m long in 12 days . What length of wall can eight men, working at the same rate , build in eight days.Give your answer to 4 significant figures (3mks)
- A shopkeeper made a loss of 20% by selling a trouser at Sh. 960 . What profit would he have made if he had sold it at sh.1500 (3mks)
- A girl spent 2/5 of her pocket money on bread and 1/6 of the remainder on stationery. If she had Ksh. 200 left at the end of the term, how much pocket money did she have at the beginning of the term. (3mks)
- Small cubes of of edge 2cm are to be packed into a rectangular container measuring 6 cm by 5 m and 4 m.How many cubes are required ? (3 mks)
- a: b =2: 3 and b: c=5:9 , find the ratio a:c (2mks)
. . - Express 0.407as a fraction. (3mks)
- Three bells ring at intervals ring at intervals of 40 minutes,45 minutes and 60 minutes.If they ring simultaneously at 6.30 am,at what time will they ring next together? (3mks)
- The area of 10 square plots is 160 ares .Find the length in metres of the side of each plot (3mks)
- Find the perimeter of a circular protractor whose radius is 14 cm (3mks)
- Convert the following decimals into percentage (3 mks)
- 0.67
- 1.25
- 0.167
ANSWER ALL THE QUESTIONS IN THIS SECTION
SECTION II (50MKS)
-
- A cylindrical can of diameter 20 cm and height 60cm is filled with water using a cylindrical jar of diameter 10 cm and height 8 cm. How many jarfuls will fill the can? (5 mks)
- Find the the surface area of an isosceles triangular prism of length 25 cm ,height 4.5 cm and base 6 cm (5 mks)
-
- Find the area of the sector of a circle of radius 3 cm if the angle subtended at the centre at the centre is 1400 .(Take pie=22/7) (4mks)
- A minor arc of a circle subtends an angle of 1050 at the centre of the circle.If the radius of the circle is 8.4 cm,find the length of the major arc (3 mks)
- Calculate the surface area of a rectangular tank measuring 5.4 cm long,3.6 cm width and 1.8 cm high. (3 mks)
-
- All prime numbers less than ten are arranged in descending order to form a number
- Write down the number formed (2 mks)
- State the total value of the second digit in the number formed in a(i) above (2 mks)
- The lengths of wires were 30 m,36 m and 84 m.Pieces of wire of equal length were cut from the three wires.Calculate the least number of pieces obtained. (6 mks)
- All prime numbers less than ten are arranged in descending order to form a number
-
- When a certain number is divided by 30,45 or 54 there is always a remainder of 21.Find the number (4 mks)
- A square toilet is covered by a number of whole rectangular tiles of sides 60 cm by 48 cm. Calculate the least possible area of the room in square metres (3 mks)
-
- Express 1050 in terms of its prime factors (1 mk)
- Determine the smallest positive number such that 1050P is a perfect square (2 mks)
- The following figure represents a piece of land . The two ends are semicircles of radius 70m each.
- Calculate
- The perimeter of the land (2mks)
- The area of the land in hectares (3mks)
- A private developer bought this piece of land at a price of Ksh 5,000,000 per hectare and later sold the all land at Kshs. 14,760,000. Determine
- The price at which he bought the whole piece of land (2mks)
- His percentage profit (3mks)
- Calculate
Marking Scheme
-
- Numerator:
= 80 + 10
=80-2(6)
80-12
=68
Denominator:
54 - 2 + 12
52+12
64
- Numerator:
-
- 0.24 + 0.243= 0.483
0.08 ÷ 0.4= 0.2
0.483
0.2
= 2.415
- 0.24 + 0.243= 0.483
-
-
2 36 54 3 18 27 3 6 9 2 3 - Other number: gcd x lcm
given number
6 x 216 = 36
36
6 x 216 = 24
54
-
-
- 3(3x+4) + 6(x+1) - 4(2x+8)
12
9x+12 + 6X+6-8x-32
12
7x-14
12 - 2x+8=14
2x=14-8
2x=6
x=3
- 3(3x+4) + 6(x+1) - 4(2x+8)
-
- Length of an arc = θ/3602πr
88cm = 144/360 x 2 x 22/7 x r
88x10=88/7r
r=880 x 7
88
r=70cm - Men Length Days
4 32 12
8 ? 8
Ratio of men; 8:4 = 2:1
Ratio of days 8:12 = 2:3
Length of wall= 2/1 x 2/3 x 32 = 128/3 = 42.67 - 80% = 960
100%=?
100 x 960 = 1200
80
1500 - 1200 = 300
300/1200 x 100 = 25% - Bread = 2/5
5/5 - 2/5 = 3/5
Stationery = 1/6 of 3/5 = 1/10
2/5 + 1/10 = 1/2
1/2 → 200
2 x 200 = 400
1 - 1US dollar = 90.45
7500
7500 x 90.45 = 678, 375
1
678, 375 - 638, 676 = 39, 699
1 Sterling pound= 132.33
? = 39699
39699 = 300
132.33 - a:b = a:b:c
5(2:3) = 10:15
b:c
3(5:9)= 15:27
a:c = 10:27 - Let r = 0.4074
10r= 4.0740
100r = 40.7407
1000r= 407.4074
999r= 407
r= 407/999
r= 11/27 -
2 40 45 60 2 20 45 30 2 10 45 15 3 5 45 15 3 5 15 5 5 5 5 5 1 1 1
2 x 2 x 2 x 3 x 3 x 5 = 360
360/60 = 6hrs
6:30 + 6= 12:30pm - 1are= 100m2
16ares= ?
16 x 100= 1600m2
√1600 = 40m
1 side = 40m - ½πD +D
d= 14 x 2= 28
22/7 x 1/2 x 28 + 28
11 x 4 + 28
44 + 28 = 72 -
- 0.67
67/100 x 100= 67% - 1.25/100 x 100 = 125%
- 167/1000 x 100 = 16.7%
- 0.67
-
- V= πr2h
1 ----- 22/7 x 10 x 10 x 60 = 132000/7
2------ 22/7 x 10 x 10 x 8 = 17600/7
132000 x 7
7 17600
=7.5
jarfuls= 8
- V= πr2h
-
- 140/360 x 22/7 x 3 x 3
= 2/4 x 22= 11cm2 - 360-105 = 255 - major arc
length= circumference= 255/360 x 22/7 x 2(8.4)
255/360 x 22/7 x 16.8
255/360 x 22 x 2.4
255/150 x 22 = 37.4cm - Sa= 2(5.4 x 3.6)+2(5.4 x 1.8)+2(3.6 x1.8)
=2(19.44)+2(9.72)+2(6.48)
=38.88+19.44+12.96
=71.28
- 140/360 x 22/7 x 3 x 3
-
-
- 75321
- 20
- 30, 36,84 -----GCD
2 30 36 84 3 15 18 42 5 6 14
2 x 3= 6m ---equal length
30/6 = 5 pieces
36/6 = 6 pieces
84/6 = 14 pieces
5 + 6 + 14 = 25 pieces
-
-
- 30, 45, 54 -----LCM
2 30 45 54 3 5 45 27 3 5 15 9 3 5 5 3 5 5 5 1 1 1 1 2 x 3 x 3 x 3 x 5 = 270
270 + 21 = 291 - 60,48 ----LCM
2 60 48 2 30 24 2 15 12 2 15 6 3 15 3 5 5 1 1 1
2 x 2 x 2 x 2 x 3 x 5 = 240
240 cm = 2.4m
2.4 x 2.4 = 5.76m2 -
- 1050 → 2 x 525
2 x 3 x 175
2 x 3 x 5 x 35
2 x 3 x 5 x 5 x 7 - 1050 = 2 x 3 x 5 x 5 x 7
1050P = 2 x 2 x 3 x 3 x 5 x 5 x 7 x 7
P = 2 x 3 x 7= 42
P= 42
- 1050 → 2 x 525
- 30, 45, 54 -----LCM
-
-
- Perimeter = 2 (1/2πD + 200)
2( 1/2 x 22/7 x 140 + 200)
2(220 + 200)
= 2(420)
= 840m - area = (200 x 140) - 2(1/2 x 22/7 x 70 x 70)
=28000 - 15400 =12600
12600m2
12600/10,000 = 1.26ha
- Perimeter = 2 (1/2πD + 200)
-
- 1.26 x 5,000,000 = 6 300 000
- 6 300 000 = 100%
14 760 000 =?
14 760 000 x 100 = 234.2857
6 300 000
234.2857 - 100 = 134.2857%
- 1.26 x 5,000,000 = 6 300 000
-
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