QUESTIONS
- (24 Marks)
- You are provided with:-
- Aqueous hydrochloric acid solution P in a beaker.
- A solution Q containing 6.3 g of dibasic acid H2C2O4.2H2O per litre.
- Aqueous sodium hydroxide solution R.
- You are required to:
- Standardize the sodium hydroxide solution R.
- Use the standardized solution R to determine the concentration of solution P in moles per litre.
PROCEDURE I
Fill the burette with solution Q. Pipette 25.0 cm3 of solution R into a conical flask and 3 drops of phenolphthalein indicator. Titrate this solution with solution Q until the pink colour just disappears .Record your results in table I below .Repeat this procedure two more times and complete table 1.
TABLE 1
1 | 2 | 3 | |
Final burette reading(cm3) | |||
Initial burette reading(cm3) | |||
Volume of solution Q used(cm3) |
(4 marks)
- Calculate the average volume of solution Q used. (1 mark)
- Calculate the concentration of the dibasic acid solution Q in moles per litre. (2 marks)
(C=12,O=16,H=1) - Calculate the number of moles of the dibasic acid solution Q used.(1 mark)
- Calculate the number of moles of sodium hydroxide in 25cm3 of solution R.(2 marks)
- Calculate the concentration of sodium hydroxide solution R in moles per litre (2 marks)
PROCEDURE II
Using a 100cm3measuring cylinder, measure 90cm3of distilled water and transfer it into a 250cm3 beaker. Dry the measuring cylinder and use it to measure 10cm3 of solution P and add it to the 90 cm3 of distilled in the beaker. Mix the solution well and label it solution T.
Fill the burette with solution T and pipette 25cm3 of solution R into a clean conical flask. Add 3 drops of phenolphthalein indicator. Titrate this solution with solution T until the pink colour just disappears .Record your results in table II below .Repeat this procedure two more times to complete table II.
Table II
1 | 2 | 3 | |
Final burette reading(cm3) | |||
Initial burette readings(cm3) | |||
Volume of solution T used (cm3) |
- Calculate the average volume of solution T used. (1 mark)
- Calculate the number of moles of solution R used.(1 mark)
- Calculate the number of moles of hydrochloric acid in solution T that reacted completely with 25cm3 of Sodium hydroxide solution R. (2 marks)
- Calculate the number of moles of hydrochloric acid in 100cm3 of solution T(2 marks)
- Determine the concentration of the original hydrochloric acid solution P in moles per litre.(2 marks)
2. (16 MARKS)
You are provided with solid A, which is a mixture of two compounds .Carry out the experiment s below .Record your observations and inferences in the table and identify any gas (es) evolved.
(a)Transfer a spatula end-full of solid A in a boiling tube and add 20cm3of distilled water. Shake thoroughly and filter .Rinse the residue with distilled water and keep both the filtrate and the residue.
Observations | Inferences |
1 mark 1mark
(b) Divide the filtrate into three portions, each of 2cm3.
(i) To portion one, add ammonia solution dropwise until in excess.
Observations | Inferences |
1 mark 1mark
(ii) To portion two, add 4 drops of 0.5M Lead (II) nitrate solution.
Observations | Inferences |
1 mark 1mark
(iii)To portion three, add 4 drops of Barium chloride solutions, followed by 5 cm3 of nitric (v) acid.
Observations | Inferences |
1 mark 1mark
c) Scrap the residue from the filter paper (a) above using a spatula and transfer it into a boiling tube. Add to it 1M Nitric acid until it dissolves .Keep the resulting solution for use in part(d) below.
Observations | Inferences |
1 mark 1mark
(d) Divide the solution into 3 parts.
(i) To part two, add ammonia solution dropwise.
Observations | Inferences |
1 mark 1mark
(ii) To part two, add 4 drops of 1M hydrochloric acid solution.
Observations | Inferences |
1 mark 1mark
(iii) To part three, add 4 drops of potassium Iodide solution.
Observations | Inferences |
1 mark 1mark
MARKING SCHEME
PROCEDURE I
TABLE I ……………. 5 Mks distributed as follows.
-
- Complete table (1 Mark)
- Complete table with 3 titrations (1 Mark)
- Incomplete table with 2 titrations ( ½ Mark)
- Incomplete table with 1 titration (0 Mark)
- Penalties
- Wrong arithmetic
- Inverted table
- Burette reading beyond 50cm3 unless where explained.
- Unrealistic titre values below 1cm3 or above 50cm3.
NB: Penalise ½ mark each to a maximum of ½ mark.
- Complete table (1 Mark)
- Use of decimals (tied to 1st and 2nd rows only) (1 Mark)
- Accept 1 or 2 d.p used consistently otherwise penalise fully.
- If 2 d.p is used, the 2nd d.p must be either ‘0’ or ‘5’ otherwise penalise fully.
- Accuracy (Tied to correct titre value) (1 Mark)
Compare the candidate titre values with the teacher titre values and mark as follows;- If at least one is within ± 0.1 of the teacher’s value. (1 Mark)
- If none is within ± 0.1, but atleast one is within ± 0.2 of teacher’s value ( ½ Mark)
NB: If there are 2 possible values from the teacher’s result, use one that is closer to candidate’s value
and mark accordingly.
- Principles of averaging (1 Mark)
Conditions- If 3 consistent values are averaged (1 Mark)
- If 3 titrations are done but only two are consistent and averaged (1 Mark)
- If 2 titrations done and are consistent and averaged. (1 Mark)
- If 3 titrations are done but are inconsistent and averaged. (0 Mark)
NB: Values averaged must differ by a maximum of ± 0.2cm3 of each other.
- Final answer (1 Mark)
(Tied to correct average titre)
Compare the candidate’s average titre with the teacher’s average titre.- If within ± 0.1 of teacher’s value. (1 Mark)
(ii) If not within ± 0.1 but within ± 0.2 of the teacher’s value ( ½ Mark)
(iii) If none is within ± 0.2 (0 Mark)
NB:
Accept final answer expressed to 2 d.p unless the answer works out to an exact figure otherwise penalise ½ Mark
- If within ± 0.1 of teacher’s value. (1 Mark)
PROCEDURE II
- Table II – 5 Marks
NB: Marks as per table I
Calculations
PROCEDURE I - Rmm of H2C2O4.2H2O = 126
. :Molarity of solution Q in moles per litre = 6.3/126 1 = 0.05 1 - Moles of dibasic acid solution Q used = (Average volume x 0.05 (ans i)) ½
1000
Correct answer ½ - 2NaOH(aq) + H2C2O4(aq) → Na2C2O4(aq) + 2H2O(l)
Acid : Base = 1:2 1
. :Moles of sodium hydroxide used = 2 x ans iii ½
Correct answer ½
NB:
If the equation is missing award zero marks for the working. - Concentration of sodium hydroxide solution R = (1000 x Ans iv)
25
Correct ans. 1
NB: Ignore if units missing but penalise ½ mark for wrong units used.
PROCEDURE II
- Moles of solution R used = (25 x Ans (v) ) ½ = Correct ans ½
1000 - NaOH(aq) + HCl(aq) NaCl(aq) + H2O(l) 1
Acid : Base = 1:1 1
. : Moles of HCl in solution T that reacted with 25cm3 of solution R = Ans ii.
NB: If Ans ii) is transferred intact to iii) but the equation is missing award zero marks. - Moles of HCl in 100cm3 of solution T = (100 x Ans iii) 1 = Corr. Ans 1
(Average volume of solution T) - Original concentration of HCl in solution P = (1000 × Ans iv) = Corr. Ans 1
10
NB: If wrong units are used penalise ½ mark but ignore if units are missing.
2. 16 Marks
OBSERVATIONS | INFERENCES | |
(a) |
| Soluble and insoluble salts present in solid A 1 |
(b) | (i) White precipitate ½ soluble in excess | Zn2+ confirmed present |
(ii) White precipitate formed 1 |
| |
(iii) White precipitate formed insoluble in nitric acid ½ | SO2-4 present 1 | |
(c) | Effervescence/bubbles produced | CO2-3 present |
(d) | (i) White precipitate ½ insoluble in excess ½ | Ca2+, Ba2+, Mg2+, Pb2+ or Al3+ present
|
(ii) White precipitate formed 1 | Pb2+ present 1 | |
(iii) Yellow precipitate formed | Pb2+ confirmed present |
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