INSTRUCTIONS.
- Answer all the questions in the spaces provided.
- You are provided with:
Solution M 0.5M Hydrochloric acid.
Solution F containing 15.3g/litre of basic compound G2X.
You are required to determine the relative atomic mass of G.
Procedure.
Place solution M in a burette, pipette 25cm3 of solution F into a 250cm3 conical flask. Add two drops of melthy/orange indicator and titrate. Record your results in the table below. Repeat the procedure two more times and complete table 1. (4mks)I II III Final burette reading Initial burette reading Volume of solution M used - What is the average volume of solution M? (1mk)
- Given that one mole of F reacts with 2 moles of M; calculate the:
- Number of moles basic compound G2X in the volume of solution F used. (1mk)
- Concentration of solution F in moles per litre. (1mk)
- Relative formula mass of the basic compound, G2X. (1mk)
- Relative atomic mass of G. (relative formula mass of X=60, atomic mass of H=1.0, O=16.0)
- You are provided with;
1.89g solid P, solid P is a dibasic acid H2X.
0.5M solution of the dibasic acid, H2X, solution V
Sodium hydroxide, solution K.
You are required to determine:- The molar heat of solution of solid P.
The heat of reaction of one mole of the dibasic acid with sodium hydroxide. - Calculate the heat of reaction of solid H2X with aqueous sodium hydroxide.
PROCEDURE 1
Place 30cm3 of distilled water into a 100ml plastic beaker. Measure the initial temperature of the water and record it in the table II below. Add all the solid Pat once; stir the mixture carefully with the thermometer until all the solid dissolves. Measure the final temperature reached and record it in the table II. (2mks)Final temperature (°C) Initial temperature (°C) - Determine the change in temperature T1. ( ½ mk)
- Calculate the;
- Heat change when H2X dissolves in water, (Assuming the heat capacity of the solution is 4.2Jg-1K-1 and density is 1g/cm3.(2mks)
- Number of moles of the acid that were used (Relative Formula mass of H2X is 126) (1mk)
- Molar heat of solution H1 of the acid H2X. (1mk)
PROCEDURE II.
Place 30cm3 of solution V into a 100cm3 beaker. Measure the initial temperature and record it in table III below. Measure 30cm3 of sodium hydroxide, solution K. Add all the 30cm3 of solution K at once to V in the beaker, stir the mixture with the thermometer. Measure the final temperature reached and record it in table III.Final temperature (°C) Initial temperature (°C) - Determine the change in temperature, T2. (½ mk)
- Determine the;
- Heat change for the reaction (assume the heat capacity of the solution is 4.2Jg-1K-1 and density is 1g/cm3) (2mks)
- Number of moles of acid used. (H2X) (1mk)
- Heat of reaction H2 of one mole of the acid H2X with sodium hydroxide. (1mk)
- Given that:
H2O
H1 is the heat fir reaction H2X(s)2H+(aq) + X2-(aq)
H2 is the heat for the reaction H+(aq) OH−(aq)H2O(l)
Calculate H3 for the reaction, H2X(s) +2OH−(aq)2H2O(l) + X2−(aq) (2mks)
- The molar heat of solution of solid P.
-
- You are provided with solid Q. Carry out test indicated below and record your observations and deductions in the table below.
- Place a spatula full of Q in a boiling tube. Add about 10cm3 of distilled water and shake. Divide the resultant mixture into 4 portions. (2mks)
Observation Inference - To the first portion, add Barium nitrate solution followed by dilute nitric acid. (1mk)
Observation Inference - To the second portion add 2 – 3 drops of sodium hydroxide till in excess. (1mk)
Observation Inference - To the third portion add 2 – 3 drops of ammonia solutions till in excess. (1mk)
Observation Inference
- Place a spatula full of Q in a boiling tube. Add about 10cm3 of distilled water and shake. Divide the resultant mixture into 4 portions. (2mks)
- You are provided with liquid X. you are required to carry the test below.
- Place 1cm3 of substance X in a test tube. Add a small piece of sodium carbonate solid. (1mk)
Observation Inference - To about 3cm3 of X in a boiling tube, add acidified potassium chromate (VI) and warm. (1mk)
Observation Inference - To about 3cm3 of x add acidified potassium manganate (VII) (1mk)
- Dip a glass rod in liquid X and ignite. (2mks)
Observation Inference
- Place 1cm3 of substance X in a test tube. Add a small piece of sodium carbonate solid. (1mk)
- You are provided with solid Q. Carry out test indicated below and record your observations and deductions in the table below.
CONFIDENTIAL
- About 50cm3 of solution V
- About 50cm3 of solution K.
- 1.89g of solid P accurately weighed into a stoppered container.
- Thermometer.
- 5 dry test tubes in a test tube rack.
- Spatula
- Bunsen burner.
- About 120cm3 of solution M.
- About 90cm3 of solution F.
- About 10cm3 of liquid X.
- Solid Q weighed about 1g.
- Blue and red litmus papers.
- A boiling tube.
- Glass rod.
Access to:
- Bunsen burner
- 2 M sodium hydroxide with a dropper.
- 2M Ammonium hydroxide with a dropper.
- Barium nitrate solution (1M)
- Lead nitrate solution (1M)
- 1M Nitric (V) acid.
- Methyl orange with a dropper.
- Acidified potassium dichromate (VI) with a dropper.
- Acidified potassium manganate (VII).

MARKING SCHEME
- You are provided with:
Solution M 0.5M Hydrochloric acid.
Solution F containing 15.3g/litre of basic compound G2X.
You are required to determine the relative atomic mass of G.
Procedure.
Place solution M in a burette, pipette 25cm3 of solution F into a 250cm3 conical flask. Add two drops of melthy/orange indicator and titrate. Record your results in the table below. Repeat the procedure two more times and complete table 1. (4mks)I II III Final burette reading Initial burette reading Volume of solution M used - CT
- D1
- A1
- PA1
- FA1
- What is the average volume of solution M? (1mk)
- Award mark for averaging of values with a range of 0.2cm3.
Volume (x) = 13.4cm3
- Award mark for averaging of values with a range of 0.2cm3.
- Given that one mole of F reacts with 2 moles of M; calculate the:
- Number of moles basic compound G2X in the volume of solution F used. (1mk)
Moles of HCl = vol x 0.2 = 0.0002 x moles
1000
Moles of G2X.10H2O = 0.0002x = 0.0001x moles
2 - Concentration of solution F in moles per litre. (1mk)
Concentration = moles x 1000
Vol
= 0.0001 x X 1000
25
= 0.004xM - Relative formular mass of the basic compound, G2X. (1mk)
R.F.M = Mass per litre
Concentration
15.3 = 3825g
0.004x x - Relative atomic mass of G. (relative formula mass of X= 60, atomic mass of H =1.0, O=16.0)
2G + 60 + 10(18) = 3825
x
2G = 3825 − 240
x
G = (3825 − 120) = G = 23
2x
- Number of moles basic compound G2X in the volume of solution F used. (1mk)
- What is the average volume of solution M? (1mk)
- You are provided with;
1.89g solid P, solid P is a dibasic acid H2X.
0.5M solution of the dibasic acid, H2X, solution V
Sodium hydroxide, solution K.
You are required to determine:-
- The molar heat of solution of solid P.
- The heat of reaction of one mole of the dibasic acid with sodium hydroxide.
- Calculate the heat of reaction of solid H2X with aqueous sodium hydroxide.
PROCEDURE 1
Place 30cm3 of distilled water into a 100ml plastic beaker. Measure the initial temperature of the water and record it in the table II below. Add all the solid Pat once; stir the mixture carefully with the thermometer until all the solid dissolves. Measure the final temperature reached and record it in the table II. (2mks)Final temperature (°C) Initial temperature (°C)
D ½
A 1- Determine the change in temperature ∆T1. ( ½ mk)
∆T = Final temp – Initial temp - Calculate the;
- Heat change when H2X dissolves in water, (Assuming the heat capacity of the solution is 4.2Jg-1K-1 and density is 1g/cm3.(2mks)
∆H = mC∆T1
= 30 × 4.2 × ∆T
1000
= 0.126 X ∆T1 KJ - Number of moles of the acid that were used (Relative Formula mass of H2X is 126) (1mk)
No of moles = Mass = 1.89 = 0.015moles
RFM 126 - Molar heat of solution H1 of the acid H2X. (1mk)
0.015 moles → 0.126 × ∆T1 KJ
1 mole → ?
1×0.126×∆T1 = −8.4 × ∆T1KJmol−1
0.015
PROCEDURE II.
Place 30cm3 of solution V into a 100cm3 beaker. Measure the initial temperature and record it in table III below. Measure 30cm3 of sodium hydroxide, solution K. Add all the 30cm3 of solution K at once to V in the beaker, stir the mixture with the thermometer. Measure the final temperature reached and record it in table III.Final temperature (°C) Initial temperature (°C)
D ½
A 1- Determine the change in temperature, T2. (½ mk)
∆T2 = Final temp – Initial temp - Determine the;
- Heat change for the reaction (assume the heat capacity of the solution is 4.2Jg-1K-1 and density is 1g/cm3) (2mks)
∆H = 60 ×4.2 × ∆T2
1000
= 0.252 X ∆T KJ - Number of moles of acid used. (H2X) (1mk)
Moles = MV = 0.5 × 30 = 0.015moles
1000 1000 - Heat of reaction H2 of one mole of the acid H2X with sodium hydroxide. (1mk)
0.015 Moles → 0.252 X ∆T2 KJ
1 mole → ?
1×0.252×∆T = −16.8 ×∆T2KJ/mol
0.015
- Heat change for the reaction (assume the heat capacity of the solution is 4.2Jg-1K-1 and density is 1g/cm3) (2mks)
- Given that: H2O
H1 is the heat fir reaction H2X(s)2H+(aq) + X2-(aq)
H2 is the heat for the reaction H+(aq) OH−(aq)H2O(l)
Calculate H3 for the reaction, H2X(s) +2OH−(aq)2H2O(l) + X2−(aq) (2mks)
H2X(s) → 2H+(aq) + X2−(aq) −8.4 X ∆T1 KJ/mol
2H+(aq) + 2OH−(aq) → 2H2O(l) – 16.8 X ∆T2 KJ/mol X2
H2X(s) + 2OH−(aq) → 2H2O(l) + X2− (aq) ∆H = −8.4T1 + −16.8 X 2T2
= −8.4T1 – 33.6T2
- Determine the change in temperature, T2. (½ mk)
- Heat change when H2X dissolves in water, (Assuming the heat capacity of the solution is 4.2Jg-1K-1 and density is 1g/cm3.(2mks)
- Determine the change in temperature ∆T1. ( ½ mk)
-
-
- You are provided with solid Q. Carry out test indicated below and record your observations and deductions in the table below.
- Place a spatula full of Q in a boiling tube. Add about 10cm3 of distilled water and shake. Divide the resultant mixture into 4 portions. (2mks)
Observation Inference Solid dissolves to produce colourless solution (1mk) Soluble salt. (1mk) - To the first portion, add Barium nitrate solution followed by dilute nitric acid. (1mk)
Observation Inference A white ppt insoluble on addition of HNO3 SO2−4 , present - To the second portion add 2 – 3 drops of sodium hydroxide till in excess. (1mk)
Observation Inference A white precipitate soluble in excess NaOH(aq) Zn2+, Pb2+ present. - To the third portion add 2 – 3 drops of ammonia solutions till in excess. (1mk)
Observation Inference A white ppt soluble in excess NH3(aq) Zn2+ present
- Place a spatula full of Q in a boiling tube. Add about 10cm3 of distilled water and shake. Divide the resultant mixture into 4 portions. (2mks)
- You are provided with liquid X. you are required to carry the test below.
- Place 1cm3 of substance X in a test tube. Add a small piece of sodium carbonate solid. (1mk)
Observation Inference No effervescence H+/ COOH absent - To about 3cm3 of X in a boiling tube, add acidified potassium chromate (VI) and warm. (1mk)
Observation Inference K2Cr2O7/H+ changes from orange to green. R-OH present - To about 3cm3 of x add acidified potassium manganate (VII) (1mk)
Observation Inference KMnO4/H+ changes from purple to colourless R – OH present - Dip a glass rod in liquid X and ignite. (2mks)
Observation Inference Burns with a blue flame - C – C – or R – OH present or saturated organic compound.
- Place 1cm3 of substance X in a test tube. Add a small piece of sodium carbonate solid. (1mk)
- You are provided with solid Q. Carry out test indicated below and record your observations and deductions in the table below.
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