SECTION A (25 MARKS)
- Five images are formed when two mirrors are inclined at an angle between them. Determine the angle of inclination (2mks)
- A soft iron ring placed between two magnets as shown in figure 1 below. Draw the magnetic field between the two magnets (2mks)
- The graph below shows the terminal voltage ,V, of a certain battery varying with the current , I, being drawn from the battery
- Write an expression relating the e.m.f E,terminal voltage V, current I,and the internal resistance, r, of the battery(1mk)
- From the graph determine the internal, r,of the battery (3mks)
- Two metallic spheres A and B stand in contact as shown below. A positively charged rod is held near sphere A
- Show charge on each when the metallic balls are separated(2mks)
- Why are the spheres supported on insulated stands (1mk)
- The chart below shows an arrangement of different parts of the electromagnetic spectrum.
Radio waves Infrared Visible A X-rays Gamma rays - Name the radiation represented by A(1mk)
- State two applications of the radiation identified in (i) above (2mks)
- A boy standing 600m away from a cliff bangs two pieces of wood together and hears an echo 3.5 seconds later. Determine the speed of sound in air at the place (3mks)
- An electric heater is made of a wire of resistance 100 and connected to a 240v mains supply. Determine the power rating of the heater (3mks)
- Figure s below shows an object O placed in front of a converging mirror of focal length15cm
Draw on the figure a ray diagram to locate the image formed (3mks) - State faradays law of electromagnetic induction (1mk)
SECTION B (55MARKS)
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- State two factors that affect the resistance of metallic conductors (2mks)
- Study the circuit below and answer the questions that follow:
- Determine the total resistance.
- Given that the total current in the circuit is 12A; ….
Determine the e.m.f of the battery (3mks)
- The figure below shows cross-section of a dry cell. Use the information on the figure to answer the questions that follow.
- Name the Parts labled A and B (2mks)
A_
B _ - State the use of the manganese (IV) oxide in the cell. (1mk)
- State what is meant by polarization in simple cells. (1mk)
- Name the Parts labled A and B (2mks)
- The figure below shows a ray of light travelling
- Calculate the refractive index of water to glass given the refractive index of glass and water are 3 / 2 and 4 / 3 respectively. (3mks)
- Calculate the angle ø (3mks)
- State the two laws of refraction (2mks)
- State the conditions to be satisfied for total internal reflection to occur (2mks)
- Define the principal focus of a diverging lens. (1mk)
- A real object of height 1cm is placed 50mm from a converging lence forms a virtual image 100mm from the lens. Determine the:
- Focal length of the lens (3mks)
- Magnification (2mks)
- On the grid provided, draw to scale the ray diagram for the set up to show how image is formed (2mks)
- State two differences between the human eye and the camera. (2mks)
- Define diffraction as applied in waves (1mk)
- The diagram below shows wave fronts approaching an opening.
- sketch the wave front after passing the opening on the same diagram (1mk)
- State what would be observed on the pattern after passing the opening if
- The gap was made larger. (1mk)
- The wave length was made larger. (1mk)
- When a metre rule was placed in a ripple tank, it was noted that the distance between 15 successive dark lines (crests) was 30cm. The frequency of the vibrator was 20Hz. Determine:
- One wave length of the waves in the ripple tank. (2mks)
- The periodic time of the wave (2mks)
- The velocity of the waves over the water surface. (3mks)
- The figure below shows a circuit that may be used to charge a capacitor
- State the observation on the millimeter when the circuit is switched on. (1mk)
- Explain the observation in a (i) above (2mks)
- The circuit above is left on far duration of time. State the value of potential difference (p.d) across;
- The resistor R (1mk)
- The capacitor C (1mk)
- Sketch the graph of potential difference V across R against time. (1mk)
- The figure below shows three capacitors connected to a 10v battery
.
Calculate:- The combined capacitance of the three capacitors (3mks)
- The change on the 5.0µf capacitor. (3mks)
- The figure below shows a circuit that may be used to charge a capacitor
MARKING SCHEME
- 360 0 – 1 = 5 ✓
= 360°/6✓
= 60 0 - E = v + Ir
- E = V + Ir
V = Ir + E ✓
r = gradient
gradient = 1.2/1.0 – 0.9/0.5
= 0.6Ω✓
- to avoid earthing /neutralizing of the sphere
- U.V
- detecting forged bank notes
Burglar alarms
Automatic door opener (any two)
- Speed = 2d/t✓
= 600x2/ 35✓
= 342.85m/s✓ - P = V2/R
= 240²/100
= 576watts - The magnitude of the induced e.m.f is directly proportional to the rate of magnetic flux linkage.
SECTION 2
- Temperature
Length of the conductor - 1/3 + ½ = 2 +3/6= 5/6
= 6 /5 =1.2Ω
Total resistance = 1.2 + 3 +4.8 = 9.0 - V = 1R
= 12 x 9
= 108V
- 1/3 + ½ = 2 +3/6= 5/6
- A – carbon rod
B – Powdered carbon and manganese (IV) oxide. - Acts as a depolarizer
- The accumulation of bubbles around the copper plate
- A – carbon rod
- Temperature
- w∏g x a∏g
¾ x 3/2 = 9/8 - n1sinQ1= n2sinO2
4/3sin30 =3/2sin
= 26.39 0 - The incident ray, the refracted ray and the normal at the point of incidence all lie in the same plane.
The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant for a given pair of media. - Light must be traveling from anoptically denser to a less dense medium
The angle of incidence must be greater than the critical angle.
- w∏g x a∏g
- The point where rays parallel and close to the principal axis appear to diverge from after being refracted by a diverging lens.
- 1/U+1/V =1/f
1/f =1/50 -1/100
100 -50/5000=50/5000 =5000/50=100mm - m=v/u =100/50 = 2
- 1/U+1/V =1/f
- focal length of human eye can be changed and for the cameral is fixed
The eye has a crystalline convex lens; the camera has a convex lens.
The eye has a retina where the image informed; the camera has a sensitive film where the image is formed.
- The spreading out of wavws when they pass through a small aperture
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- .
-
- The length wave will be less.
- The wave length will also be larger after diffraction.
- 30 /2 =15cm =0.15m
- T = 1/f = 1/20 = 0.05s
- V = f
= 0.05 x 0.15
= 0.0075m = 0.75cm
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- The millimeter deflects to maximum then falls back to zero
- Current flows when the capacitor is charging. When fully charged, no flows and potential difference (p.d) is equal to charging voltage.
- V R = 0 volts
- VC = 5 volts
- CP=1/ cp=¼ +1/5 = 9/20 ⇒ 20/9=2.22µf
Total capacitance, C T = 2.22 + 3 = 5.22µf = 5.22 x 10 -6 F - Change on series Q = CV
= 22.2 10 = 22.2µc
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