Question

In fourteen years time, a mother will be twice as old as her son. Four years ago, the sum of their ages was 30 years. Find how old the mother was, when the son was born.

Answer 1

Let mother's years be x and son's be y
x+14= 2(y +14)
x+14= 2y + 28
x-2y = 14

(x-4)+(y-4) = 30
x +y = 38

   (x- 2y= 14)
  -(x+ y= 38)
= -3y=-24
=3y=24
y=8( son's age currently)
x+y=38
x=30( mother's age currently)
At son's birth, mother's age = 30-8=22 years