The figure below shows a cuboid labelled ABCDEFGU Point O is the mid point of BD. AB 15 cm, BC =8 cm and CF=5 cm.

Calculate the angle between the lines OF and OF

∢EOF=EO = OF = √5^{2} + 8.5^{2}= 9.8615 ^{a2} = b^{2} + c^{2} − 2bc Cos A15^{2} = 9.8615^{2} + 9.8615^{2} − 2 x 9.8615^{2} cos Acos A = −0.156822A = 99.02

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