# The distance between two towns A and B is360km.A minibus left town A at 8.15a.m and travelled towards B at an average speed of 90km/hr. A matatu left town B at 10.35a.m on the same day and travelled towards A at an average speed of 110km/hr.

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The distance between two towns A and B is360km.A minibus left town A at 8.15a.m and travelled towards B at an average speed of 90km/hr. A matatu left town B at 10.35a.m on the same day and travelled towards A at an average speed of 110km/hr.

1.
1. how far from A did they meet?
2. at what time did the two vehicles meet?
2. A motorist left his home at 10.30a.m on the same day and travelled at an average speed of 100km/hr. He arrived at B at the same time as minibus. Calculate the distance from B to his home.

1.

1. Distance travelled by minibus when matatu leaves B
90 × 21/3 = 90 × 7/=210km
R.d = 360 − 210 =150
R.s = 90 + 110 = 200
t = 150 ×60 =45mins
200
Distance minibus has travelles = 90 × 35/60
=90 × 185 =277.5km
60
2. 10.35
+ .45
11.20
=11:20am
2. Time minibus reached B
360  = 4hrs
90
8.15 + 4 = 12.15pm
Time motorist took = 12.15
−10.30
1.45
=1hr 45mins
d= 100 × 145/60
=100 × 13/4
=100 × 7/4 =175km