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60cmof oxygen diffuses through a porous pot in 50 seconds. How long would it take 60cm3 of oxygen gas diffuses through a porous pot in 50sec.How long would it take 60cm3 of Sulphur (iv) oxide to diffuse through the same pot under the same conditions?

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Time of diffussion
M(SO)g =32+16×2
           =64
M=16 × 2
      =32
Time of diffusion 2
         =50 × √2
         =70.7seconds

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