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A stone of mass 4.0kg immersed in water and suspended from a spring balance with a string. The beaker was placed on a compression balance whose reading was 85N. The density of the stone was 3000kg/m-3while the density of the liquid was 800kg/m-3. Determine the;

  1. Volume of the liquid displaced. 
  2. Upthrust on the stone.
  3. Reading on the spring balance.

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  1. Volume of the liquid displaced. 
    • V = 4/3000 
      V = 1.33 x 103m3  (At least 2 d.p)
  2. Upthrust on the stone. 
    • Upthrust = Weight of liquid displaced = vĪg
      Liquid; 800 x 1.33 x 103 x 10
      = 10.64 N
      Upthrust in water = v
      1.33 x 103m3 x 10 x 1000
      = 13.33N 
  3. Reading on the spring balance.
    • Weight of stone in air = 40N
      Readings â†’ 40 – 10.64 = 29.36N
      Or
      40 – 13.33 = 26.67N  
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