Physics Paper 2 Questions and Answers - Form 3 End Term 2 Exams 2023

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Section A (25 marks)

  1. Give one difference between luminous and non-luminous sources of light. (1mk)
  2.  When a negatively charged rod is brought near the cap of a leaf electroscope, the leaf rises.
    Explain this observation, (2mks)
  3. Figure 2 represents a displacement-time graph for a wave.

    F3PYHSICSPP2ET22022A3
    Determine the frequency of the wave. (2mks)
  4. State the conditions necessary for a wave incident on a slit to be diffracted. (2mrks)
  5. In an experiment to determine the focal length of a concave mirror, magnification M was determined for various image distances v. Figure 3 shows a graph of magnification M against image distance v for the results from the experiment.
    F3PYHSICSPP2ET22022A5

    Given that M = 1 v/determine the focal length f of the mirror. (3mks)
  6. A hair dryer is rated 2500W, 240V. Determine its resistance. (2mks)
  7. Figure 4 shows the magnetic field pattern round a current-carrying conductor. Indicate on the conductor the direction of the current. (1mk)
          F3PYHSICSPP2ET22022A7
    Figure 4
  8. Why is repulsion the sure test for a magnet? (1mk)
  9. Figure 5 shows a ray of light incident on an air bubble which is inside water,
    F3PYHSICSPP2ET22022A9
    Complete the ray to show the path it follows through the air bubble. (1mk)
  10. Explain how polarization of a cell increases the cell’s internal resistance. (2mks)
  11.  
    1. A positively charged material was brought close to an insulated metallic ball as shown in Fig 4. State and explain the distribution of charge in the ball (2mks)
      F3PYHSICSPP2ET22022A11
    2. Explain why sound cannot be heard from far when one shouts in a forest (1mk)
  12. Using the variation of resistance with temperature, differentiate between a conductor and a semiconductor. (1mk)
  13. A cell of internal resistance O.5 ? is in a circuit containing a 10 ? resistor. A current of 2A flows in the circuit. Determine the emf of the cell. ( 2mks)


Section B (55 marks)

  1.  
    1.  
      1. State Snell’s law of refraction of light (1mk)
      2. Give two advantages of totally internally reflecting prisms over plane mirrors. (2mks)
    2. A ray of light is incident on a kerosene water interfaces as shown in 
      F3PYHSICSPP2ET22022A14
      Given that the refractive index of water and kerosene are 1.33 and 1.44 respectively,
      Determine
      1. the refractive index for the kerosene – water interface (3mks)
      2. determine and show on the figure the path of the rays of light between the Kerosene-water surface (3mks)
      3. Why does the colours of the light separate at the kerosene layer. (1mk)
      4. State and explain the observation that the eye above the two surfaces would see (2mks)
  2.  
    1. State Ohm’s law (1mk)
    2. The figure 8 below shows a circuit with a coil used to warm oil in a beaker.
      F3PYHSICSPP2ET22022A15
      1. Explain how heat is produced in the coil (2mks)
      2. Given that the reading of the ammeter is 2.4A determine the resistance of the coil. (3mks)
      3. How much heat is produced in the coil in a minute? (3mks)
      4. Give two changes that can be made in the set up in order to produce more heat per minute. (2mks)
  3.  
    1. Define capacitance of a capacitor (1mk)
      The figure below shows a charged electroscope two aluminium plates A and B arranged a shown
                F3PYHSICSPP2ET22022A16
      State and explain the observations made when:
      1. d is reduced (2mks)
      2. the plate A is more horizontally (2mks)
      3. a sheet of polythene is placed between A and B (2mks)
    2. Three capacitors are connected to a 10V battery as shown below.
                F3PYHSICSPP2ET22022A16b
      1. Calculate the combined capacitance (3mks)
      2. What is the charge on the 3 μF ? capacitor (3mks)
  4. Students set up a mass attached to spring such that when it oscillates it taps on water surface in a wide shallow tank.
    F3PYHSICSPP2ET22022A17
    The students measured time for 20 oscillations and found that the mass takes 36 seconds.
    1. Determine the periodic time of the mass (2mks)
    2. Calculate the frequency of the waves produced on the water surface (3mks)
    3. Given that the student counted four ripples between the mass and end B of the tank,
      Determine the speed of the waves. (3mks)
  5.  
    1. A machine is a device that enables work to be done more easily and conveniently. State any two ways in which a machine makes work easier. (2marks)
    2. Figure 7 shows a wheel and axle being used to raise a load W by applying an effort E. The radius of the wheel is R and of the axle is r.
                     F3PYHSICSPP2ET22022A18
      1. Show that the velocity ratio (V.R) of this machine is given by R/ (3 Marks)
      2. Given that r = 5cm and R = 50cm, determine the effort required to raise a load of 200N if the efficiency of the machine is 90%. (3 mks)
    3. An airtight flask containing a gas is connected to a mercury manometer. The levels of mercury in the two limbs of the manometer are as shown in the diagram below.
                      F3PYHSICSPP2ET22022A18c
      Calculate the pressure of the gas (Density of mercury = 1.36 x 10 4 kg/m 3 and atmospheric pressure = 1.0 x10 5 N/m 2 ) (3mks)
    4. State one way of making the surface tension of a liquid stronger               (1mk)


MARKING SCHEME

SECTION A

 1  A lumious source of light emits light while a non-lumious source reflects light  1mks 
 2  Electrons are repelled from the cap and flow to the leaf and plate. Repulsion between
 the electrons on the plate and those on the leaf causes the leaf to rise.
 2mks
 3       f =  Number of waves         =    1¾       = 50H3
         
        Timetaken                   35 x 10–3
 Alt.
      f =  =      1                 
           T        (25 – 5) x 10–3 = 50H3
 2mks
 4   Width of the aperture/ slit should be approximately or nearly equal to λ of the incident wave;  2mks
 5                0.9 – 0.4         – 1
Slope =     3 –  7       =     f
          =   – 0.5
                  5     =  0.125
         f = 8cm
 3mks
 6              v2                  v2 = 2402
     
p =    R           R =  P     2500
                              = 24.04Ω
 2mks
 7        F3PYHSICSPP2ET22022A7b  1mk
 8  Repulsion only occurs between like poles of magnets while attract also occur between a magnet and a magnetic material   1mk
9 F3PYHSICSPP2ET22022A9b  1mk
10  Hydrogen gas bubbles form around the positive plate. The hydrogen gas insulates the positive plate thus increasing internal  resistance   2mks
11  Electrons are attracted towards the rod leaving the atoms at the other end of the ball with net positive charges
 Trees absorb sound

2mks

1mks

12  In conductor the resistance increases with increase in temperature while in a semiconductor the resistance reduces with  increase in temperature. 1mk
13  E = Ir + IR 
    = 2 x 0.5 + 2 x 10
    = 11V 
 2mks
    SECTION B  
14
  1.  
    1. The ratio of the sine of angle of incidence to the sine of angle of refraction is a constant for a pair of media
    2. Do not absorb light energy like mirrors
      Not affected by thickness as mirrors
      Do not wear off like the peeling of siyvering on mirror.
  2.  
    1. k°w = k°a a°w
      1    x 1.33 = 0.9236
       1.44
    2. = 70°
      Sini = 0.9236
      Sinr
      Sin r   = sin 70° = 1.0174
      0.9236
      r is greater than 90° hence the light reflection
      F3PYHSICSPP2ET22022A14b
    3. The different colours travel at different velocities hence would have different angles of refraction and are dispersed
    4. The eye would see a spectrum since the light rays are dispersed in the kerosene layer and are internally reflected at the kerosene – water surface the eye would see a spectrum at the surface

 1mk

2mks

3mks













1mk

2mks

15
  1. Current flowing through a conductor is directly proportional to the potential difference across it provided the temperature and other physical conditions are kept constant
  2.  
    1. The work done in driving charges through the coil is high due to its resistance. This energy is converted into heat in the coil
    2. V = IR            R =     = 12V
                                   I           2.4
                                           = 5.0Ω
    3. H = VIt
      H = 12 x 2.4 x 60
      = 1728J
    4. Using a source with higher emf
      Reducing the length of the coil
      = P = V2
                R

 1mk


2mks




3mks

3mks

2mks

16
  1. capacitance c is the charge stored in a capacitor per unit voltage
    1. the deflection of the leaf decreases since the pd reduces with the distance of separation, the greater the deflection, the smaller the capacitance.
    2. the deflection of the decreases since the pd increases with the area of overlaps or the greater the deflection the smaller the capacitance.
    3. the deflection of the leaf decreases, the capacitance increases ,since the smaller the deflection the greater the capacitance.
  2.  
    1.               C2C3
          C = C1 + C2 + C3
               μF + 4 x 4
            =3       4 + 4
            =3 μF + 2μF
            =5 μf
    2. Charge on the 3 μF capacitor is the same as the overall charge Q =CV
                                                                                                                =5.0 x 10
                                                                                                                =50C

 1mk

 

2mks

2mks

 

2mks

3mks

 

 

 

3mks

17
  1. T = T = 36 = 1.8s
          20   20
  2. f = 1 = 1 = 0.5556Hz
         
    T   1.8
  3. 80cm ⇒ S4λ
    V = fλ
    =
    1 x 0.2 = 0.111m/s
      1.8

 2mks

3mks

 

3mks

18
  1.  A small force (effort) is used to overcome a large force (Load)
    • Less energy is expended in doing work
    • Less time is used in accomplishing the task
    1. In one revolution, both wheel and axle complete one circumference
      •  V.R = Effort Distance/Load distance = 2 πR/2πr
      • V.R = R/r
    2. V.R = 50/5 = 10
      M.A = efficiency x V.R/100 = 90x10/100 = 9
      Effort = Load/M.A          = 200/9             = 22.22N
  2. Gas Pressure = At.Pressure – Pressure due to Hg Volumn
    Pg = 1.0x105 – 0.4 x 13600x10
    = 94560N/m2
  3. By lowering the temperature of the liquid

 2mks

 

 

3mks

 

3mks

 

3mks

 

1mk

 

 

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