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What is  the formula of products of a mixture of Ethanol and Butanoic acid with few drops of sulphuric (vi) acid?

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The reaction between ethanol (C2H5OH) and butanoic acid (C3H7COOH) with a few drops of sulfuric acid (H2SO4) can lead to the formation of an ester through an esterification reaction. The general formula for the product of an esterification reaction is:
R1COOH + R2OH → R1COOR2 + H2O
In this case, R1 represents the alkyl group of butanoic acid (C3H7-) and R2 represents the alkyl group of ethanol (C2H5-). Therefore, the formula for the product, which is an ester, would be:
C3H7COOC2H5 + H2O
This product is known as ethyl butanoate.

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