1. P=KQ3
√R
35 = K x 8 x 8 x 8
√144
35=512k/12
K= 105/128
P = 105Q3
128√R
P= 105 x 203
128 x √225
= 105 x 8000m
128 x 15
=437.5
2. Original value of P =KQ3
√R
new value = K x (0.76Q)3
√1.4R
= 0.438976KQ3
1.1832√R
= 0.3710 KQ3
√R
change = (0.3710 -1) KQ3
√R
0.6290KQ3
√R
%change = -0.6290 x 100
-62.90%
P has decreased by 62.90%