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The line whose equation is 2x − 3y=12 cuts the x-axis and y-axis at A and B respectively. Find the equation of the line equidistant from A and B.

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3y=2x−12
  y=2/3x − 4
y=−3/2
A(6, 0)
B(0,−4)
M(3,−2)
y+2 = −3
x−3     2
2y+4=−3x+9
2y=−3x+5

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