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In the diagram below, determine the equation of the line XY in the form y = mx + c

correction F1ET1mathQ12

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midpoint (−2+4) , (7+−1)
                     2         2
        (2,3)
gradient = 7+1 = 8 = 4
                     4+2    6     3
¾ × 4/3 m1 = −1 × ¾
             m1 =−¾
y−3 = −¾
x−2
4y − 12 =−3x + 6
4y = −3x + 18
4        4       4
y = −¾x + 9/2

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