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A man uses 100m of fencing to enclose a rectangular area using a wall on one side. Find the maximum possible area that can be enclosed.

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Let length be x
w=100-2x
         2
A=x(50 − x)
dA =50−2x
dX
       50−2x =0
            x=25
max=25 × 25
      =625m2

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625m2
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456m2
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