when 4 g of metal carbonate was dissolved in 160 cubic centimetre of 1M hydrochloric acid and then the resultant solution diluted to 1 L, 25 cm of the solution required 20 cubic centimetre of 0.1 M sodium hydroxide solution for complete neutralisation calculate the number of moles per litre of exercise hydrochloric acid that reacted with sodium hydroxide

Question

When 4 grams of metal carbonate was dissolved in were 60 cubic centimeter of 1 mole hydrochloric acid and then the resultant solution diluted to one liter 25 cubic centimeter of this solution required 20 cubic centimeter of 0.1 mole sodium hydroxide solution for complete neutronization calculates the number of moles per liter of excess hydrochloric acid that reacted with sodium hydroxide