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factorization questions
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asked
Mar 18
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Mathematics Form 3
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0799903XXX
Factorization questions
further logarithms
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log^x=log^5-log(2x+3)
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log^x=log^5-log(2x+3)
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log^x=log^5-log(2x+3)
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log2[3x+8]-3=log2[x-4]
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solve: log (3x+8)-3log2=log x-4
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