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50cm3 of oxygen gas diffused through a porous plug in 80 secs. How long will it take 100cm3 of sulphur (IV) oxide to diffuse through the same plug? (S = 32 0= 16)

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If 50cm3 → 80sec
  100cm3→ ?
100×80 =160sec
    50
Sulphuric dioxide diffusing a plug
  160  =  √32
TSO   √64
TSO2  = 160 × 8
                  √32
          =226.27417sec

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