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An air bubble with a volume of 1 cmescapes from the helmet of a diver at a depth of 200 m below the water surface. What will be the volume of the bubble immediately it breaks the surface of water? (Take atmospheric pressure = 10 m of water) 

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P1V1 = P2V2
P1 = (200 +10)m
V1 = 1cm3
P2 = 10m
v2 = ?
210m x 1cm3 = 10m x V2
v= 210/10
=21cm3

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