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The sides of a triangle were measured and recorded as 4cm,6.2cm and 9.50cm.Calculate the percentage error in its perimeter correct to 2 decimal places.

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A.E =(4.5 + 6.25 + 9.505)-(3.5 + 6.15 + 9.495) 
                                         2
=20.255-19.145=1.11
             2             2
=0.555
% error=0.555 x100
                 19.7
=2.32%

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