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Masses of three babies was stated as a=12.7kg, b=9.8 kg and c=3.20kg. find the relative error in the following expressions:

  1. a+b-c
  2. c÷ab 

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  1. Absolute error = 0.05 + 0.05 + 0.005 = 0.105
    Working (a+b-c)= 12.7+9.8 − 3.2 = 19.3
    Relative error =   0.105/19.3 = 0.005440
                                     
  2. Relative error = 0.05/12.7 + 0.05/9.8  + 0.0053.2 = 0.01060
                                        
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