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The figure 6.0 below shows a network of capacitors.
PhycF4T1P2Q12
Determine the combined capacitance of the network.

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For series 1/Cs = 1/3 + 1/1
1 + 3 =4/3
       3        
Cs = 3/4 = 0.75µF
for parallel : Ce = (2 + 0.75)µF
= 2.75µF

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