Solve for x in log 5–2+log(2x+10)=log(x–4)

log 5 − 2 log10 + log(2x+10) = log(x−4) Log ^{(5}/_{10}^{2} × (2x +10) ) =log(x−4) ^{x}/_{10} + ½ = x − 4^{−9}/_{10}^{x} = ^{−9}/_{2 } x = −9 × 10 2 −9 =5

6.3k questions

9.6k answers

6 comments

590 users