Simplify the expression

num (3t−5a)(3t+5a) den 6t^{2} +9at+10at+15a^{2} =3t(2t+3a) +5a(2t+3a) =(3t+5a)(2t+3a) (3t−5a)(3t+5a) = 3t−5a(3t+5a)(2t+3a) 2t+3a

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