Question

1. Draw the graph of y=(2x–3)(x–1) for the interval –2 ≤ x ≤ 4 
2. use your graph to solve
   1. 2x²–5x+3=0 
   2. 2x²=3x+2 

Answer 1

1. y=2x² − 2x − 3x +3
   y=2x² − 5x +3

   x	−2	−1	0	1	2	3	4
   2x2	8	2	0	2	8	18	32
   −5x	10	5	0	−5	−10	−15	−20
   3	3	3	3	3	3	3	3
   y	21	10	3	0	1	6	15

   
   
2.  
   1. y=0
      x=0
   2.    y=2x² − 2x − 3x +3   −y=2x2 − 5x +3
        0=2x² − 3x −2
        y =−2x +5

      x	0	−1	1
      y	5	7	3

      x=2
      y=−0.45