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An element B consists of three isotopes of mass, 28, 29 and 30 and percentage abundances of 92.2, 4.7 and 3.1 respectively. Show that the relative atomic mass of element is 28.11

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92.2 x 28 + 4.7 x 29 + 3.1 x 30 = R.A.M
       100          100          100
25.816 + 1.363 + 0.93 = 28.11

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