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A person stands between two vertical cliffs 400m from the nearer cliff. The cliffs are x distance apart. Every time the person strikes the rock once, two echoes are heard, the first one after 2.5s and the second one 2.0 s later. Calculate

  1. the speed of the sound in air 
  2. the value of x

1 Answer

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  1. s = 2d
    2 x 400
    = 320ms−1
  2. 2(x − 400) = (2.5 +2)s  
    x = 1120m 

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