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A person stands between two high walls d metres apart. He stands 400m from the nearer wall. He blows a whistle and hears two echoes, the first one after 2.5 seconds and the second one 2 seconds later. Determine:

  1. The speed of sound in the air. 
  2. The value of d

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  1. v = 2d = 2×400
           t        2.5
      =320ms−1
  2. v = 2d 
           t 
    d = vt = 320(2.5+4.5)
           2             2
       =1120m
    OR
    d − 400 = 320 × 4.5
                           2
    d = 720+400
       =1120m
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