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Figure 6 shows the velocity-time graph of the motion of a stone thrown vertically upwards.
qn10

From the graph, determine the maximum height reached by the stone.

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at maximum height v = 0
displacement = area under the graph
=20m
 alternatively:
v2 = u2 - gh
0= 202 - 2 x 10h
h= 400/20
h =20m

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