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The sum of digits in a two digit number is 16. When the number is subtracted from the number formed by reversing the digits the difference is 18. Find the number.

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Let 10th digit be x
0 x =y
X+y=1b(i)
10y +a –(10x +y) =18
10y+x-10x-y=18
9y-9x=18
y-x=2(ii)
y+x=18
y+x=16
2y 0=18
Y=9
X=7
Number
79

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