The figure below shows a circle centre O. Chord AB subtends 30° at the centre. If the area of the minor segment is 5.25cm^{2}, find the radius of the circle.

30 × 22 × r^{2} = 11 r^{2}360 7 42Area of ∆ = ½r^{2} sin 30 = ¼r^{2 } 11 r^{2} − ¼r^{2} =5.254284 × 1 r^{2} =5.25 × 84 84 r^{2} = 441r^{2} = √441 r = 21cm

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