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An element F has a relative atomic mass of 88. When a current of 0.5 amperes was passed through the fused chloride of F for 20 minutes and 20 seconds, 0.278g of F were deposited at the cathode. Determine the charge on ion of F (1Faraday = 9650ºC).

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Quantity of electricity Q=It
9650ºc→ 1 Faraday 
61º → 0.006321244 x 88/0.278
The change on the ion is +2 

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