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10cm3 of a gaseous hydrocarbon, CxHy required 30cm3 of oxygen for complete combustion. If steam and 20cm3 of Carbon (IV) oxide were produced, what is the value of x in CxHy

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CxHy(g)+O2(g)→CO2(g)+H2O(g) 
10cm3    30cm3       20cm3
Their volumes to mole ratio
CxHy(g)+O2(g)→CO2(g)+H2O(g) 
1mole    3moles      2moles
CxHy(g)+3O2(g)→2CO2(g)+H2O(g) 
Then 2 atoms of carbon were present in CxHy and 4 atoms of Hydrogen.
C2H4(g)+3O2(g)→2CO2(g)+2H2O(g)
Thus x = 2

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