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A ball is dropped from the top of a vertical cliff 45m high. Given that the velocity just before striking the sandy beach is 30m/s, and the ball penetrate the sand to a depth of 10cm determine its average retardation.

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v2 = u2 + 2as 
O2 = 9002 + 2 x a x 0.10
-900 = 0.20 a
a = (-900)/0.20
a = -450 m/s2 

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