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A factory uses 100 kg of ammonia each day to produce 160 kg of nitrogen(II) oxide. Calculate the percentage yield of nitrogen(II) oxide.

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Moles of NH3 =100,000 =5882.35
Moles of NO = mole ratio 1:1
Molar mass NH3 =17       Molar mass N=30✓½
Mass of NO = 5882.35 × 30 =176470.58
%yield of No =  160,000176,470  × 100 =  90.667%   
    OR           160 × 17  × 100/ 30 x 100   =90.67%

                                                             
                                       

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