0 votes
676 views
in Physics Form 2 by
A helical spring extends by 1 cm when a force of 1.5N is applied to it. Find the elastic potential energy stored in it.

1 Answer

0 votes
by

Elastic PE = ½Fe
=½ × 1.5 × 0.01
= 7.5 × 10−3J

Welcome to EasyElimu Questions and Answers, where you can ask questions and receive answers from other members of the community.

6.4k questions

9.6k answers

6 comments

590 users

...