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A uniform wooden bar of length 1m and mass 5kg is pivoted at 40cm mark as shown below. Calculate the value of F1.
F2Et1phyQ14

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0.2xF1= 0.6x100N=300N
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0.2*F1=0.1*50
F1=25
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0.2*F1=0.1*50
F1=25
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