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in Mathematics Form 3 by
Solve simultaneous equation
XY=4
X+Y=5

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3
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X=5-Y
(5-y)y=5
5y-y²=5
5y+y²+5=0
Y²+5y+5=0
S=5
P=5

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x+y=5
Let x=5-y
xy=4 then be
(5-y)y=4
after this you use the completing square method
and get your answer as:
y=4
x=1


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Y=4
X=1
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When x=4,Then y=1
When x=1,Then y=4
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22
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X=4 
Y=1

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