Find the radius as the center of a circle whose equation is3x^{2} + 3y^{2} + 18y -12x – 9=0

X^{2} + y^{2} – 4x+6y-3=0X^{2}-4x+4 + y2+6y +9=3+4+9(x-2)2 +(y+3)2=16Centre (2,-3) radius=4

5.9k questions

8.2k answers

6 comments

590 users