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Given that 2x2−kx+18 is a perfect square, find k and hence solve the equation 2x2−kx+18=0 by factorization. 

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(−k)2 = 2 × 18
( 2 )
     K2 =36 × 4
         =144
       K=±12
2x2 − 12x + 18 = 0
2x2 − 4x − 9x + 18 = 0
2x(x−2) −9(x−2) = 0
(x−2) (2x−9) = 0
x = 2
x=4½

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