Given that 2x^{2}−kx+18 is a perfect square, find k and hence solve the equation 2x^{2}−kx+18=0 by factorization.

(−k)^{2} = 2 × 18( 2 ) K^{2} =36 × 4 =144 K=±122x^{2} − 12x + 18 = 02x^{2} − 4x − 9x + 18 = 02x(x−2) −9(x−2) = 0(x−2) (2x−9) = 0x = 2x=4½

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