Use completing square method to solve for X in.½ x^{2 }– ^{5}/_{2x }+ 1 =0

x^{2 }– 5x + 2 =0x^{2} – 5x + C = −2 + Cx^{2} – 5x + (^{5}/_{2})^{2 }= −2 + 6.25(x – ^{5}/_{2})^{2} = 4.25X – 2.5 = ±2.061X = ±2.061 + 2.5X= 2.561 or 0.439

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