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  1. State the mathematical expression of Boyle’s Law
  2. In an experiment, 375cm3 of gas P have a pressure of 800mmHg at 25°C. what will be the volume if pressure is reduced to 720mmHg under the same temperature? 

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  1. P1V1 = P2V2
  2. P1 = 800mmHg  P2 = 720mmHg
    V1 = 375 cm3    V2 = ?
    P1V1 = P2V2

    V2 = P1V1=(800 × 375)=416.7cm3 
               P2         720

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asked Mar 6, 2022 in Chemistry Form 3 by Justinamutheu
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