0 votes
138 views
in Physics Form 1 by
A hydraulic jack has a piston (large piston) diameter of 0.32m while its plunger (small piston)has a diameter of 0.052m. A force of 500N is exerted on the plunger. Determine the upward force in the large piston.

1 Answer

0 votes
by

d= 0.32m
f= ?
f= 500
d= 0.052m
f1/A1=F2/A2

F2= F1/A1 X A2

=      500      X π X 0.162
   π X 0.0262  

= 18935 N 

Welcome to EasyElimu Questions and Answers, where you can ask questions and receive answers from other members of the community.

5.5k questions

6.5k answers

8 comments

590 users

...