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A hydraulic jack has a piston (large piston) diameter of 0.32m while its plunger (small piston)has a diameter of 0.052m. A force of 500N is exerted on the plunger. Determine the upward force in the large piston.

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d= 0.32m
f= ?
f= 500
d= 0.052m
f1/A1=F2/A2

F2= F1/A1 X A2

=      500      X π X 0.162
   π X 0.0262  

= 18935 N 

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