Calculate angle PAQ.

< PAQ = <PAM + <QAM

< PAM = sinθ1 =^{4.5}/_{10.5}=0.4286

Sin ^{-1} (0.4286) = 25.38º

< QAM = <PAM = 25.38º

→<LAP = 25.38x2= 50.76º

Calculate angle PBQ.

<PBQ = < PBM + <QBM

< PBM = sin∝1 =^{45}/_{84}=0.5357

Sin-1 (0.5357) = 32.39º

< PBM = <QBM = 32.39º

<PBQ = 32.390x 2 = 64.78º

Calculate the area of the shaded part.

area of segment = area of a section – area of D

Taking (i)

=

= 48.84 – 42.69 = 6.15cm^{2}

Taking (ii)

=

= 39.89 – 31.92 = 7.97cm^{2}

= (6.15 + 7.97) cm^{2} = 14.12cm^{2}