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20cmof oxygen diffused through a porous partition in 70s .how long would it take 20cm3. Of sulphur VI oxide to diffuse through the same portion under the same condition. 

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Mo2 = 2 × 16 =32         Mso3 =(32+16×3) = 80 
To2 =70secs                Tso3 =?
grahams law of diffusion
Tso3 = √80
 70      √32
Tso3 = 70√80 = 70×8.944  =110secs
            √32          5.657

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